If it's not what You are looking for type in the equation solver your own equation and let us solve it.
v^2-9v-18=0
a = 1; b = -9; c = -18;
Δ = b2-4ac
Δ = -92-4·1·(-18)
Δ = 153
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{153}=\sqrt{9*17}=\sqrt{9}*\sqrt{17}=3\sqrt{17}$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-3\sqrt{17}}{2*1}=\frac{9-3\sqrt{17}}{2} $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+3\sqrt{17}}{2*1}=\frac{9+3\sqrt{17}}{2} $
| 2x^2x=5 | | (5x−1)(x+1)=0 | | -9(6+7a)=34 | | -42=d/4-50 | | -2f−10=f+6+2 | | n+53+n9=319 | | 3.4*z+14.05=-1.42+2.1*z | | 17v+4v-19v+4v+3v=18 | | 7n−10=5n+10 | | 5x+3=-21+3x | | a-3/7=27 | | -4x^2+6x−16=-5x^2 | | 2(x-5)-4=-22 | | (3/9)=(y/6) | | -5z=-3-4z | | (1/2)^(x-2)=2^x | | 3x+6=x+2= | | -5z=-4z+5 | | x=9x+7 | | -10-7m=-6m-6 | | -4x2+6x−16=-5x2 | | 4^(3x-3)=(1/32) | | 2n=-8+n | | -10-6n=-10n+10 | | 7=5.8+x | | -20+13*c=20+11*c | | 20w-19w-w+4w=12 | | 2-n=4n-13 | | 8y=9y+4 | | x2+2x=3. | | 14+13y=20y=21 | | 7/17x=35 |